Resolver los siguiente sistemas de ecuaciones lineales:
A) 2·X-Y=1 B) X-Y=0 C) -X+4·Y=-1
X+Y=0 X+Y=1 2·X-3·Y=0
A) X+Y=0 B) X+Y=0 C) X-2Y=1
2X+2Y=4 2X+2Y=0 -2X+4Y=-2
A) 2X+4Y=1 B) 2X+4Y=1 C) 2X+4Y=1 3X+6Y=3/2 3X+6Y=3 3X+4Y=0A) (3/2)X+(2/3)Y=1 B) (1/2)X+(1/4)Y=(1/8) (2/3)X-(3/2)Y=0 (1/3)X-(1/5)Y=(1/5)A) (3/2)X+(2/3)Y=1 B) (1/2)X+(1/4)Y=(1/8) (2/3)X-(3/2)Y=0 (1/3)X-(1/5)Y=(1/5)
A) (3/2)X+(2/3)Y=1 B) (1/2)X+(1/4)Y=(1/8) (2/3)X-(3/2)Y=0 (1/3)X-(1/5)Y=(1/5)LIC:OSIRISMELISA DAVILA


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